Help balancing oxidation-reduction reactions in acidic solution?
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Hi. I have a homework question about balancing oxidation-reduction reactions. I did not learn this yet in school, so I am having some trouble. Here is the problem:
Balance the following oxidation-reduction reactions that occur in acidic solution: a. Zn(s) + HCl(aq) --> Zn2+(aq) + H2(g) b. I-(aq) + ClO-(aq) --> I3-(aq) + Cl- (aq) I have started working it out, but I am stuck. Here's what I've done so far. For (a): 1) Write the oxidation and reduction half-reactions. Zn --> Zn2+ H+ --> H 2) Balance each half-reaction. Zn --> Zn2+ + 2e- e- + H+ --> H 2(e- + H+ --> H) 2e- + 2H+ --> 2H 3) Add the half-reactions and cancel identical species. Zn + 2e- + 2H+ --> Zn2+ + 2e- + 2H Zn + 2H+ --> Zn2+ + 2H After this, I'm not sure what I have to do. I know I have to add in the Cl from the original reaction, but I'm not sure where to do it. For (b), I am not sure how to write the half-reactions. Thanks for helping! |
Similar Questions: Help balancing oxidation reduction reactions acidic solution
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Recent Questions About: Help balancing oxidation reduction reactions acidic solution
Answers
Answer from Librarian50
A trial-and-error approach to balancing chemical equations involves playing with the equation
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Goals for Balancing Chemical Equations
1. The number of atoms of each element on both sides of the equation is the same and therefore mass is conserved. 2. The sum of the positive and negative charges is the same on both sides of the equation and therefore charge is conserved. (Charge is conserved because electrons are neither created nor destroyed in a chemical reaction.) There are two situations in which relying on trial and error can get you into trouble. Sometimes the equation is too complex to be solved by trial and error within a reasonable amount of time. Consider the following reaction, for example. 3 Cu(s) + 8 HNO3(aq) 3 Cu2+(aq) + 2 NO(g) + 6 NO3-(aq) + 4 H2O(l) Other times, more than one equation can be written that seems to be balanced. The following are just a few of the balanced equations that can be written for the reaction between the permanganate ion and hydrogen peroxide, for example. |
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Sources:
http://chemed.chem.purdue.edu/genchem/topicre |
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Answer from onsakthi
The Half-Reaction Method of Balancing Redox Equations.
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Balancing Oxidation-Reduction Equations
A trial-and-error approach to balancing chemical equations involves playing with the equation--adjusting the ratio of the reactants and products--until the following goals have been achieved. Goals for Balancing Chemical Equations 1. The number of atoms of each element on both sides of the equation is the same and therefore mass is conserved. 2. The sum of the positive and negative charges is the same on both sides of the equation and therefore charge is conserved. (Charge is conserved because electrons are neither created nor destroyed in a chemical reaction.) There are two situations in which relying on trial and error can get you into trouble. Sometimes the equation is too complex to be solved by trial and error within a reasonable amount of time. Consider the following reaction, for example. 3 Cu(s) + 8 HNO3(aq) -----> 3 Cu2+(aq) + 2 NO(g) + 6 NO3-(aq) + 4 H2O(l) Other times, more than one equation can be written that seems to be balanced. The following are just a few of the balanced equations that can be written for the reaction between the permanganate ion and hydrogen peroxide, for example. 2 MnO4-(aq) + H2O2(aq) + 6 H+(aq) -----> 2 Mn2+(aq) + 3 O2(g) + 4 H2O(l) 2 MnO4-(aq) + 3 H2O2(aq) + 6 H+(aq) -----> 2 Mn2+(aq) + 4 O2(g) + 6 H2O(l) 2 MnO4-(aq) + 5 H2O2(aq) + 6 H+(aq) -----> 2 Mn2+(aq) + 5 O2(g) + 8 H2O(l) 2 MnO4-(aq) + 7 H2O2(aq) + 6 H+(aq) -----> 2 Mn2+(aq) + 6 O2(g) + 10 H2O(l) Equations such as these have to be balanced by a more systematic approach than trial and error. |
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Sources:
http://chemed.chem.purdue.edu/genchem/topicre |
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Comments on this question:
that is exactly what is says in my book. and it does some kind of weird like you mentioned.
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HCl -> H2 + Cl2
which you then have to balance. I feel that something is missing from the equation.